we’ve only learned two equation formulas for free fall:
v=gt
d=1/2gt^2
and two for speed / acceleration:
s=d/t
a= V2 – V1
————
T2 – T1
so don’t make them too complicated please !

Momentum = Mass * velocity ===> Mo = MV
Impulse = Force * Time ====> I = FT
Impulse = Momentum ===> I = Mo
Force * time = Mass * Velocity ====> FT = MV
Distance = 0.5*Gravity* Time^2 + initial velocity * Time in seconds = 0.5 * 9.8 m/s^2 * Time in seconds^2 + initial velocity * Time in seconds
d = 0.5AT^2 + V1*T
Velocity = Acceleration * Time + initial velocity = 9.8 m/s^2 * Time in seconds + Initial Velocity
V = AT + V1
Force = Mass * acceleration = M * 9.8 m/s^2
F = MA

During a certain time interval, a 20N object free-falls 10m. How much kinetic energy does the object gain during this time?
please explain the formulas i need to use and how i would use them
thank you

Ball bearings can be made by letting spherical drops of molten metal fall inside a tall tower-called a shot tower-and solidify as they fall.
a) I f a bearing needs 4.0s to solidify enough for impact , how high must the tower be?
b)Whats the bearing’s impact velocity?

Relaxation Visualization

Weight = Acceleration*Mass
Acceleration of the free fall is the earth gravity that is 9.797 645 m/s²
Weight = 9.797645*Mass
free-falling object is an object which is falling under the sole influence of gravity; such an object has an acceleration on Earth of 9.8 m/s/s, downward. This numerical value for the acceleration of a free-falling object is such an important value that it has been given a special name. It is known as the acceleration of gravity – the acceleration for any object moving under the sole influence of gravity. As a matter of fact, this quantity known as the acceleration of gravity is such an important quantity that physicists have a special symbol to denote it – the symbol g. The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s/s.
There are slight variations in this numerical value (to the second decimal place) which are dependent primarily upon altitude. The Physics Classroom will use the approximated value of 10 m/s/s in order to reduce the complexity of the many mathematical tasks performed with this number. By so doing, you will be able to better focus on the conceptual nature of physics without sacrificing too much in the way of numerical accuracy. When the moment arises that you need to be accurate (such as in lab work), use the more accurate value of 9.8 m/s/s.
g = 10 m/s/s, downward
the acceleration is the rate at which an object changes its velocity. Between any two points in an object’s path, acceleration is the ratio of velocity change to the time taken to make that change. To accelerate at 10 m/s/s means to change your velocity by 10 m/s each second.
a = dv/t = 10/1 = 10
then if a body falls in the first second his speed is 10m/s and in the 2nd second is 20m/s and so on

soaps, wipes, ect ect ect

A baseball is thrown upward. The initial speed is 32 ft/sec and the initial height is 0 ft. Given the Galileo’s formula for free fall as follows:
y(t) = – 0.5g(t)^2 + v(subzero)t + y(subzero)
with gravity as 32 ft/second^2
a) When will the baseball hit the ground (in seconds)?
b) How high will it go?
c) In order for the baseball to reach a height of 36 feet, how fast must it be thrown initially?

vf=(1/2)-9.8m/s(t)^2 i think

i am trying to find the maximum force at time of impact of a free falling object, it weighs 1200 lbs, it is released and falls 5 ft, the time it takes to hit bottom is .5 seconds. im not sure if im doing it right, please help.

A raindrop fell from a cloud and hit the ground 8 seconds after it left the cloud. Use the free fall formula. g= -32 ft/sec squared